Problem spliting position - Programming and Scripting Forum

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	Problem spliting position

Somedude15 Guest
Quote
2024-01-19 23:44:27

Hi beautiful people, i have this piede of code i'm working on:


/*
   <action jsname="action_Duplicar" description="Duplicate the position and rotation of an object">
      <property name="NodeToClone" type="scenenode" description="Select the node to clone"/>
      <property name="TargetNode" type="scenenode" description="Select the node to move to"/>
   </action>
*/
action_Duplicar = function () {

};
action_Duplicar.prototype.execute = function (currentNode) {

  var newscenenode = this.NodeToClone;
  posicionVector3 = ccbGetSceneNodeProperty(this.TargetNode, "Position");
  print(posicionVector3);
  var [x, y, z] = posicionVector3;
  print(x);
  print(y);
  print(z);
ccbSetSceneNodePositionWithoutCollision(newscenenode,x,y,z);
  ccbSetSceneNodeProperty(newscenenode, "Rotation", (ccbGetSceneNodeProperty(this.TargetNode, "Rotation")));
};

when i do a print(posicionVector3); it returns the actual position of the object, but when i try to print the values of x,y and z it shows 0 for the 3 of them.
¿somebody knows what i'm doing wrong?

Thanks.

okeoke Registered User
Quote
2024-01-20 06:59:33

You cant assign variables to object properties like that:

var [x, y, z] = posicionVector3;

This would only work in case positionVector3 is an array, but it is an object with properties x, y, z. You can access them like posicionVector3.x, posicionVector3.y, and posicionVector3.z;

var x = posicionVector3.x;
var y = posicionVector3.y;
var z = posicionVector3.z;

If you want to do it one line you can also do:

var [x, y, z] = [posicionVector3.x, posicionVector3.y, posicionVector3.z];

Though, I'm not sure the last one works with CopperCube version of JS engine.

Guest Guest
Quote
2024-01-20 07:13:33

var pos = ccbGetSceneNodeProperty(cube, "Position");

ccbSetSceneNodeProperty(newCube, "Position", pos.x, pos.y, pos.z);

Somedude15 Guest
Quote
2024-01-20 15:31:30

Thanks people.

Somedude15 Guest
Quote
2024-01-20 15:34:19

Though, I'm not sure the last one works with CopperCube version of JS engine.

Yes the line

  var [x, y, z] = [posicionVector3.x, posicionVector3.y, posicionVector3.z];

Works.

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